document.write( "Question 1157076: How much pure gold (24K) must be mixed with 70% gold to get 30 grams (g) of 80% gold? Express in decimal form rounded to one decimal place. \n" ); document.write( "
Algebra.Com's Answer #779875 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "How much pure gold (24K) must be mixed with 70% gold to get 30 grams (g) of 80% gold? Express in decimal form rounded to one decimal place.
\n" ); document.write( "
Let amount of pure gold be G
\n" ); document.write( "Then amount of 70% gold = 30 - G
\n" ); document.write( "We then get: G + .7(30 - G) = .8(30)
\n" ); document.write( "G + 21 - .7G = 24
\n" ); document.write( "G - .7G = 24 - 21
\n" ); document.write( ".3G = 3
\n" ); document.write( "Amount of pure gold, or \"highlight_green%28matrix%281%2C6%2C+G%2C+%22=%22%2C+3%2F.3%2C+%22=%22%2C+10%2C+g%29%29\" \n" ); document.write( "
\n" );