document.write( "Question 1157058: How many five card hands consisting of 2 kings and 3 aces can be dealt from a
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Algebra.Com's Answer #779862 by Edwin McCravy(20056)\"\" \"About 
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How many five card hands consisting of 2 kings and 3 aces can be dealt from a
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document.write( "4 suits CHOOSE 2 for the kings = 4C2 = (4×3)/(2×1) = 12/2 = 6 ways.  They are\r\n" );
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document.write( "K♥ K♦  .  .  .\r\n" );
document.write( "K♥ K♠  .  .  . \r\n" );
document.write( "K♥ K♣  .  .  .\r\n" );
document.write( "K♦ K♠  .  .  .\r\n" );
document.write( "K♦ K♣  .  .  .\r\n" );
document.write( "K♠ K♣  .  .  .\r\n" );
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document.write( "For every one of those 6 ways to have the kings, we can put 3 aces with them any\r\n" );
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document.write( "4 suits CHOOSE 3 for the aces = 4C3 = (4×3×2)/(3×2×1) = 24/6 = 4 ways.  \r\n" );
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document.write( "They are:\r\n" );
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document.write( ".  .  A♥ A♦ A♠\r\n" );
document.write( ".  .  A♥ A♦ A♣\r\n" );
document.write( ".  .  A♥ A♠ A♣\r\n" );
document.write( ".  .  A♦ A♠ A♣\r\n" );
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document.write( "That's 6 times 4 or 6×4 or 24 ways to have such a 5-card poker hand.\r\n" );
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document.write( "Edwin
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