document.write( "Question 1157037: The denominator of a fraction is four more than the numerator. If both numerator and denominator are increased by six, the simplified result is 7/9. Find the original fraction.
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Algebra.Com's Answer #779810 by josmiceli(19441) $\"\"$ $\"About$

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Let the numerator = $\"+x+\"$
\n" ); document.write( "The fraction is:
\n" ); document.write( " $\"+x+%2F+%28+x%2B4+%29+\"$
\n" ); document.write( "-------------------
\n" ); document.write( "given:
\n" ); document.write( " $\"+%28+x+%2B+6+%29+%2F+%28+x+%2B+4+%2B+6+%29+=+7%2F9+\"$
\n" ); document.write( " $\"+%28+x+%2B+6+%29+%2F+%28+x+%2B+10+%29+=+7%2F9+\"$
\n" ); document.write( "Multiply both sides by $\"+9%2A%28+x+%2B+10+%29+\"$
\n" ); document.write( " $\"+9%2A%28+x+%2B+6+%29+=+7%2A%28+x+%2B+10+%29+\"$
\n" ); document.write( " $\"+9x+%2B+54+=+7x+%2B+70+\"$
\n" ); document.write( " $\"+2x+=+16+\"$
\n" ); document.write( " $\"+x+=+8+\"$
\n" ); document.write( "and
\n" ); document.write( " $\"+x+%2B+4+=+12+\"$
\n" ); document.write( "--------------------
\n" ); document.write( "The fraction is $\"+8+%2F+12+\"$
\n" ); document.write( "-------------------------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+x+%2B+6+%29+%2F+%28+x+%2B+10+%29+=+7%2F9+\"$
\n" ); document.write( " $\"+%28+8+%2B+6+%29+%2F+%28+8+%2B+10+%29+=+7%2F9+\"$
\n" ); document.write( " $\"+14+%2F+18+=+7%2F9+\"$
\n" ); document.write( " $\"+%28+2%2F2+%29%2A%28+7%2F9+%29+=+7%2F9+\"$
\n" ); document.write( " $\"+7%2F9+=+7%2F9+\"$
\n" ); document.write( "OK \n" ); document.write( "

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