document.write( "Question 1157013: 20.\r
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document.write( "I need help graphing the following and listing the directions,vertex,axis of symmetry,table with 5 points and the graph for this equation\r
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document.write( "f(x)=x^2-2x-5 \n" );
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Algebra.Com's Answer #779790 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! the vertex x point is at -b/2a and b is -2 and a is the coefficient of x or 1 \n" ); document.write( "so the vertex x point is +1 \n" ); document.write( "f(1)=1-2-5=-6 \n" ); document.write( "so the vertex is at (1, -6)\r \n" ); document.write( "\n" ); document.write( "The axis of symmetry is the x-value or x=1\r \n" ); document.write( "\n" ); document.write( "for 5 points, \n" ); document.write( "first pick x=0, and f(0)=-5. that is easy \n" ); document.write( "the vertex is a point, so you have that. \n" ); document.write( "Try -1 and you get 1+2-5=-2 \n" ); document.write( "try 2 and you get -5 \n" ); document.write( "because -1 is two units away from 1, and +3 is two units away from 1, and the function is symmetrical, the y-values are the same. So f(-1)=f(3)=-2 \n" ); document.write( "if you look at f(-2) three units from the axis, f(4) is also 3 units away, and they have the same y-value.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |