document.write( "Question 1156971: Find the ordered pair (a,b) of real numbers for which has a non-real root whose cube is 343. \n" );
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Algebra.Com's Answer #779760 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "First we want a cubic equation whose three roots are the three cube roots of 343.\r\n" ); document.write( "We know that since 7³=343, that the REAL cube root of 343 is 7. So the cubic\r\n" ); document.write( "equation we are looking for to begin with is:\r\n" ); document.write( " \r\n" ); document.write( " x³ = 343\r\n" ); document.write( "\r\n" ); document.write( "whose roots are the three cube roots of 343, which are the real root 7, and the\r\n" ); document.write( "two non-real cube roots of 343. Get 0 on the right\r\n" ); document.write( "\r\n" ); document.write( " x³ - 343 = 0\r\n" ); document.write( "\r\n" ); document.write( "Factor: (x - 7)(x² + 7x + 49) = 0\r\n" ); document.write( "\r\n" ); document.write( "Use zero-factor property:\r\n" ); document.write( "\r\n" ); document.write( " x - 7 = 0; x² + 7x + 49 = 0\r\n" ); document.write( " x = 7; \r\n" ); document.write( "\r\n" ); document.write( "So x² + 7x + 49 = 0 has a non-real root whose cube is 343. In fact it has\r\n" ); document.write( "two of them!\r\n" ); document.write( "\r\n" ); document.write( "Answer: \r\n" ); document.write( "\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |