document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1156966>Question 1156966</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Lydia invested <BR>\n" );
document.write( "$1700 in an account that pays 2.75% interest compounded annually. Assuming no deposits or withdrawals are made, find how much money Lydia would have in the account 7 years after her initial investment. Round to the nearest tenth (if necessary).<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #779749 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=779749\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Formula for Amount when calculating Compound Interest\r<BR>\n" );
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document.write( "A=P(1+(r/100)^tn\r<BR>\n" );
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document.write( "an initial investement of $1700<BR>\n" );
document.write( "at 2.75% annual interest,<BR>\n" );
document.write( "compounded 1 times per year,<BR>\n" );
document.write( "after 7 year(s).\r<BR>\n" );
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document.write( "A = 1700*(1+0.0275)^7\r<BR>\n" );
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document.write( "=2055.50\r<BR>\n" );
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