document.write( "Question 1156877: Hi\r
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document.write( "An alloy contains copper and silver. The amount of silver exceeds copper by 50 grams. After 25 percent of the original amount of silver was added to the alloy,the new alloy contains 60 percent silver.\r
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document.write( "Find the original amount of silver and copper. \r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #779665 by mathslover(157)![]() ![]() You can put this solution on YOUR website! Let the amount of copper be x. \n" ); document.write( "Therefore amount of silver = x+50 \n" ); document.write( "25% of original silver = \n" ); document.write( " =.25(x+50)\r \n" ); document.write( "\n" ); document.write( "Total silver after addition = \n" ); document.write( " = \n" ); document.write( "\n" ); document.write( "Total weight of the alloy after addition of silver = \n" ); document.write( "\n" ); document.write( "Since new weight of silver is 60% = \n" ); document.write( "\n" ); document.write( "=> \n" ); document.write( "=> \n" ); document.write( "=> \n" ); document.write( "=> \n" ); document.write( "=>125= .5x \n" ); document.write( "therefore, x = 250 \n" ); document.write( "Weight of copper is 250g \n" ); document.write( "Weight of silver is 250+50 = 300g \n" ); document.write( " |