document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1156764>Question 1156764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In right triangle ABC with right angle at C\r<BR>\n" );
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document.write( "AB=17\r<BR>\n" );
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document.write( "BC=8\r<BR>\n" );
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document.write( "Find MN if M and N are midpoints of AB and BC respectively. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #779658 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=779658\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "By connecting M with N you form another right angled triangle MNB with the right angle at N.<BR>\n" );
document.write( "Therefore, MN^2 + NB^2 = MB^2<BR>\n" );
document.write( "MN^2 = MB^2 - NB^2<BR>\n" );
document.write( "MN^2 = 8.5^2 - 4^2<BR>\n" );
document.write( "MN^2 = 56.25<BR>\n" );
document.write( "MN = 7.5.<BR>\n" );
document.write( "The other way is:-<BR>\n" );
document.write( "By trig ratio find what angle B is.<BR>\n" );
document.write( "cos B = adjacent/hypotenuse<BR>\n" );
document.write( "cos B = 4/8.5<BR>\n" );
document.write( "B = 61.9 degrees<BR>\n" );
document.write( "Now, using Cosine rule:-<BR>\n" );
document.write( "b^2 = m^2 + n^2 - 2 x m x n x Cos (61.9)  <BR>\n" );
document.write( "b^2 = 16 + 72.25 - (2 x 4 x 8.5 x Cos (61.9))<BR>\n" );
document.write( "b^2 = 56.2<BR>\n" );
document.write( "b = 7.498 or 7.5 (1 decimal place)<BR>\n" );
document.write( "Hope this helps. :-) </SPAN>\n" );
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