document.write( "Question 1156867: Mr. Rosoff works in the lab at a pharmaceutical company. He needs to make 44 liters of a 32% acid solution to test a new product. His supplier only ships a 48% and a 26% solution. Mr. Rosoff decides to make the 32% solution by mixing the 48% solution with the 26% solution. How much of the 48% solution will Mr. Rosoff need to use?
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document.write( "[A] 12 L [B] 44 L [C] 21 L [D] 32 L \n" );
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Algebra.Com's Answer #779644 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! Same idea, different values; see #1156869: \n" ); document.write( "https://www.algebra.com/algebra/homework/word/mixtures/Mixture_Word_Problems.faq.question.1156869.html \n" ); document.write( "https://www.algebra.com/algebra/homework/word/mixtures/Mixture_Word_Problems.faq.question.1156869.html\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--- \n" ); document.write( "---\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This example, he is supplied with 48% and 26% solutions; and he wants to make 44 liters of 32% solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Final concentration needs to be 32%, or 0.32 in decimal fraction.\r \n" ); document.write( "\n" ); document.write( "If variable v is for the amount of 48% solution to use, then 44-v is the amount of the 26% solution to use.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To account for the PURE amount of substance in the solutions:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Now solve for v.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "- \n" ); document.write( " |