document.write( "Question 1156867: Mr. Rosoff works in the lab at a pharmaceutical company. He needs to make 44 liters of a 32% acid solution to test a new product. His supplier only ships a 48% and a 26% solution. Mr. Rosoff decides to make the 32% solution by mixing the 48% solution with the 26% solution. How much of the 48% solution will Mr. Rosoff need to use?
\n" ); document.write( "[A] 12 L [B] 44 L [C] 21 L [D] 32 L
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Algebra.Com's Answer #779644 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
Same idea, different values; see #1156869:
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\n" ); document.write( "\n" ); document.write( "This example, he is supplied with 48% and 26% solutions; and he wants to make 44 liters of 32% solution.\r
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\n" ); document.write( "\n" ); document.write( "Final concentration needs to be 32%, or 0.32 in decimal fraction.\r
\n" ); document.write( "\n" ); document.write( "If variable v is for the amount of 48% solution to use, then 44-v is the amount of the 26% solution to use.\r
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\n" ); document.write( "\n" ); document.write( "To account for the PURE amount of substance in the solutions:\r
\n" ); document.write( "\n" ); document.write( "\"highlight_green%2848v%2B26%2844-v%29=32%2A44%29\"
\n" ); document.write( "Now solve for v.\r
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\n" ); document.write( "\n" ); document.write( "\"48v%2B26%2A44-26v=32%2A44\"
\n" ); document.write( "\"%2848-26%29v%2B26%2A44=32%2A44\"
\n" ); document.write( "\"%2848-26%29v=32%2A44-26%2A44\"
\n" ); document.write( "\"highlight_green%28v=44%2832-26%29%2F%2848-26%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"v=44%286%2F22%29=highlight_green%2844%283%2F11%29=v%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"highlight%28v=12%29\"-----------liters of the 48%
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\n" ); document.write( "\"highlight%2832%29\"-------------liters of the 26%
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