document.write( "Question 1156825: Two circles of radius 10 cm are drawn so that their centers are 12 cm apart. The two points of intersection determine a common chord. Find the length of this chord. \n" ); document.write( "

Algebra.Com's Answer #779615 by ikleyn(52816) $\"\"$ $\"About$

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document.write( "Notice that this chord BISECTS the segment, connecting the centers (it is clear from symmetry).\r\n" );
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document.write( "Thus the right angled triangle arises with the hypotenuse of 10 (the radius) and the leg of 12/2 = 6 cm long.\r\n" );
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document.write( "Hence, half of the chotd has the length of   = 8 cm.\r\n" );
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document.write( "It means that the entire chord is 8 + 8 = 16 cm long.    ANSWER\r\n" );
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