document.write( "Question 960751: The radiator of a truck contains 12 gallons of water. We draw off 3 gallons and replace it by alcohol, then draw off 3 gallons of the mixture and replace it by alcohol,etc., until 8 drawings and replacement have been made. How much alcohol is in the final mixture? \n" ); document.write( "
Algebra.Com's Answer #779587 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "The analysis by the other tutor is faulty.... \n" ); document.write( "And if you evaluate the expression he shows for the amount of alcohol after the 8 drawings and replacements, it is more than 12 gallons -- which of course is nonsense. \n" ); document.write( "I did some ugly calculations for the first few drawings and replacements and noticed a clear pattern in the results; then I verified my calculations using an excel spreadsheet. \n" ); document.write( "Then I finally saw the simple explanation of the pattern I saw, and thus an easy path to the answer to the problem. \n" ); document.write( "Each time a drawing and replacement is made, 1/4 of the mixture is taken out and replaced with pure alcohol. That means that with each drawing and replacement, the amount of water remaining gets reduced by a factor of 3/4. \n" ); document.write( "So after 8 drawings and replacements, the amount of water remaining is \n" ); document.write( " \n" ); document.write( "So the amount of alcohol in the radiator at that time is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |