document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107142>Question 107142</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can someone please help me solve this problem? 3(x-2)-5(2x-1)>0. The greater than sign should have a _ under it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77957 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77957\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3(x-2)-5(2x-1)>=0<BR>\n" );
document.write( "3x-6-10x+5>=0<BR>\n" );
document.write( "-7x-1>0<BR>\n" );
document.write( "-7x-1+1>0+1<BR>\n" );
document.write( "-7x>1<BR>\n" );
document.write( "-7x/-7>1/-7<BR>\n" );
document.write( "x<-1/7 reverse the inequality sign dividing or multiplying by a negative number.<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );