document.write( "Question 1156751: Suppose that a circle is tangent to both axes, is in the third quadrant, and has a radius of \sqrt(2). Find the center-radius form of its equation. \n" ); document.write( "
Algebra.Com's Answer #779514 by MathLover1(20850)\"\" \"About 
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if a circle is tangent to both axes, is in the third quadrant, and has a radius of \"sqrt%282%29\", the center will be at (\"-sqrt%282%29\", \"sqrt%282%29\")\r
\n" ); document.write( "\n" ); document.write( "the center-radius form of its equation is:\r
\n" ); document.write( "\n" ); document.write( "\"%28x-%28-sqrt%282%29%29%29%5E2%2B%28y-sqrt%282%29%29%5E2=%28sqrt%282%29%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2Bsqrt%282%29%29%5E2%2B%28y-+sqrt%282%29%29%5E2=2\"\r
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