document.write( "Question 1156751: Suppose that a circle is tangent to both axes, is in the third quadrant, and has a radius of \sqrt(2). Find the center-radius form of its equation. \n" ); document.write( "
Algebra.Com's Answer #779513 by ikleyn(52787)\"\" \"About 
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document.write( "Then the center is at the point  (\"-sqrt%282%29\",\"-sqrt%282%29\")  and the radius is  \"sqrt%282%29\".\r\n" );
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document.write( "Therefore, the standard form equation of this circle is\r\n" );
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document.write( "    \"%28x%2Bsqrt%282%29%29%5E2\" + \"%28y%2Bsqrt%282%29%29%5E2\" = 2.\r\n" );
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