document.write( "Question 106761: A recent report stated that when eating a sandwich, 32% of U.S. adults cut it in half before eating it. If 9 U.S. adults are selected at random, what is the probability that exactly 4 cut their sandwich in half before eating it? \n" ); document.write( "
Algebra.Com's Answer #77951 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
It is a binominal problem with n=9, p=0.32, x = 4
\n" ); document.write( "P(x=4) = 9C4(0.32)^4(0.68)^5 = 0.192094...
\n" ); document.write( "---------
\n" ); document.write( "I used binompdf(9,0.32,4) on a TI-83 calculator.
\n" ); document.write( "=============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );