document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1156701>Question 1156701</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three consecutive terms of a geometric sequence are:\r<BR>\n" );
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document.write( "2a-2,2a+2,5a+1. Determine the value<BR>\n" );
document.write( "of each of the terms. Use these term values to determine the equation(s) for the general term of<BR>\n" );
document.write( "the sequence (tn). (think quadratic) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #779452 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=779452\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> adjacent terms have the same ratio<BR>\n" );
document.write( "so (2a+2)/(2a-2)=(5a+1)/(2a+2)<BR>\n" );
document.write( "Therefore,<BR>\n" );
document.write( "4a^2+8a+4=10a^2-8a-2<BR>\n" );
document.write( "so 0=6a^2-16a-6<BR>\n" );
document.write( "or 3a^2-8a-3=0<BR>\n" );
document.write( "(3a+1)(a-3)=0<BR>\n" );
document.write( "a=3, or -1/3<BR>\n" );
document.write( "the terms are 4, 8, 16 with common ratio 2  or -8/3, 4/3, -2/3 with  common ratio -1/2<BR>\n" );
document.write( "a, ar, ar^2,...or <BR>\n" );
document.write( "4*2^r for r>=0<BR>\n" );
document.write( "(-1)^r*(8/3)*(1/2)^(r-1) for r=1, 2,3,... </SPAN>\n" );
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