document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1156669>Question 1156669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5.<BR>\n" );
document.write( "https://answers.yahoo.com/question/index?qid=20200421142850AABqqOP </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #779420 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=779420\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two ends are areas of circles with radii 6. That is 36 pi for each or 72 pi m^2 altogether.\r<BR>\n" );
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document.write( "If you unwrap the cylinder, there is a rectangle with width 10 (the height0 and 2 pi r  the perimeter of a circle that the cylinder is0, and that circle has radius 6, so that is 2 pi *6 or 12 pi m^2\r<BR>\n" );
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document.write( "The total is 84 pi m^2. </SPAN>\n" );
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