document.write( "Question 1156641: The length of a rectangle is 7 inches longer than it is wide. If the perimeter is 38 inches, what are the dimensions of the rectangle? width? length?
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Algebra.Com's Answer #779395 by MathLover1(20850) $\"\"$ $\"About$

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if the length $\"L\"$ of a rectangle is $\"7\"$ inches longer than it is wide $\"W\"$ , we have\r
\n" ); document.write( "\n" ); document.write( " $\"L=W%2B7\"$ .....eq.1\r
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\n" ); document.write( "\n" ); document.write( "if the perimeter is $\"38\"$ inches, we have\r
\n" ); document.write( "\n" ); document.write( " $\"2%28L%2BW%29=38\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"L%2BW=38%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"L%2BW=19\"$ ......substitute $\"L\"$ from eq.1\r
\n" ); document.write( "\n" ); document.write( " $\"W%2B7%2BW=19\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2W=19-7\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"2W=12\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"W=6\"$ \r
\n" ); document.write( "\n" ); document.write( "go to\r
\n" ); document.write( "\n" ); document.write( " $\"L=W%2B7\"$ .....eq.1, ....substitute $\"W\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"L=6%2B7\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"L=13\"$ \r
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\n" ); document.write( "\n" ); document.write( " the dimensions of the rectangle are: the length is $\"13\"$ and the width is $\"6\"$ \r
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