document.write( "Question 1156638: Molly is 4 times as old as Jill. The sum of their ages is 60. What are their ages?
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Algebra.Com's Answer #779385 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Answers: \n" ); document.write( "Molly is 48 years old \n" ); document.write( "Jill is 12 years old\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "============================================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Work Shown: \n" ); document.write( "M = Molly's age \n" ); document.write( "J = Jill's age \n" ); document.write( "Molly is 4 times old as Jill, meaning \n" ); document.write( "Molly's age = 4*(Jill's age) \n" ); document.write( "M = 4*J\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Their ages add to 60 \n" ); document.write( "M+J = 60 \n" ); document.write( "4J + J = 60 ... replace M with 4J \n" ); document.write( "5J = 60 \n" ); document.write( "5J/5 = 60/5 ... divide both sides by 5 \n" ); document.write( "J = 12 \n" ); document.write( "Jill is 12 years old\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "M = 4*J \n" ); document.write( "M = 4*12 \n" ); document.write( "M = 48 \n" ); document.write( "Molly is 48 years old\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: \n" ); document.write( "M+J = 60 \n" ); document.write( "48+12 = 60 \n" ); document.write( "60 = 60 \n" ); document.write( "The answers are confirmed. \n" ); document.write( " \n" ); document.write( " |