document.write( "Question 1156610: A motorboat maintained a constant speed of 15
\n" ); document.write( "
\n" ); document.write( "miles per hour relative to the water in going 44
\n" ); document.write( "
\n" ); document.write( "miles upstream and then returning. The total time for the trip was 7.5
\n" ); document.write( "
\n" ); document.write( "hours. Use this information to find the speed of the current.
\n" ); document.write( "

Algebra.Com's Answer #779352 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "                   SPEED        TIME          DISTANCE\r\n" );
document.write( "\r\n" );
document.write( "UP                  15-c        44/(15-c)        44\r\n" );
document.write( "\r\n" );
document.write( "RETURN              15+c        44/(15+c)        44\r\n" );
document.write( "\r\n" );
document.write( "TOTAL                            7.5\r\n" );
document.write( "

\n" ); document.write( "\"44%2F%2815-c%29%2B44%2F%2815%2Bc%29=7.5\"\r
\n" ); document.write( "\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( "\"c=sqrt%28%287.5%2A15%5E2-2%2A44%2A15%29%2F7.5%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"highlight%28c=7%29\"
\n" ); document.write( "
\n" );