document.write( "Question 1156558: How many gallons of 20% alcohol solution and 50% alcohol solution must be mixed to get 9 gallons of 30% alcohol solution?\r
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Algebra.Com's Answer #779310 by MathTherapy(10552) $\"\"$ $\"About$

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\n" ); document.write( "How many gallons of 20% alcohol solution and 50% alcohol solution must be mixed to get 9 gallons of 30% alcohol solution?
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Let amount of 20% solution be T\r\n" );
document.write( "Then amount of 50% solution = 9 - T\r\n" );
document.write( "We then get the following: .2T + .5(9 - T) = .3(9)\r\n" );
document.write( ".2T + 4.5 - .5T = 2.7\r\n" );
document.write( ".2T - .5T = 2.7 - 4.5\r\n" );
document.write( " - .3T = - 1.8\r\n" );
document.write( "Amount of 20% solution, or \r\n" );
document.write( "You should now be able to find the amount of 50% solution to mix!

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