document.write( "Question 1156580: In a church choir the ratio of males to females is 2:3. On one Sunday service ten male members were absent and six new female members joined the choir as guests for the day. If on this day the ratio of males to females was 1:3, how many regular choir members does the choir have? \n" ); document.write( "
Algebra.Com's Answer #779307 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
In a church choir the ratio of males to females is 2:3.
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document.write( "\"M%2FF=2%2F3\"\r\n" );
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document.write( "On one Sunday service ten male members were absent and six new female members joined the choir as guests for the day. \r\n" );
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document.write( "Then the ratio was\r\n" );
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document.write( "\"%28M-10%29%2F%28F%2B6%29\"\r\n" );
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document.write( "If on this day the ratio of males to females was 1:3, \r\n" );
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document.write( "\"%28M-10%29%2F%28F%2B6%29=1%2F3\"\r\n" );
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document.write( "how many regular choir members does the choir have?\r\n" );
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document.write( "Solve this system:\r\n" );
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document.write( "\"system%28M%2FF=2%2F3%2C%28M-10%29%2F%28F%2B6%29=1%2F3%29\"\r\n" );
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document.write( "Cross multiply both equations:\r\n" );
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document.write( "\"system%28M%2FF=2%2F3%2C%28M-10%29%2F%28F%2B6%29=1%2F3%29\"\r\n" );
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document.write( "\"system%283M=2F%2C3%28M-10%29=1%28F%2B6%29%29\"\r\n" );
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document.write( "\"system%283M=2F%2C3M-30=F%2B6%29\"\r\n" );
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document.write( "\"system%283M=2F%2C3M-36=F%29%29\"\r\n" );
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document.write( "From the second equation, substitute (3M-36) for F \r\n" );
document.write( "in the first equation, and solve to find M. Then substitute \r\n" );
document.write( "what you get for M in 3M-36=F to find F. \r\n" );
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document.write( "I'll give you only the answer for the number of females, F=36.\r\n" );
document.write( "You find the number of men and add them to find the number of\r\n" );
document.write( "regular choir members.\r\n" );
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document.write( "Oh crap!  The other tutor already gave you the answer, darn it!\r\n" );
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document.write( "Edwin
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