document.write( "Question 1156495: One number is 3 times another. The sum of their reciprocals is
\n" );
document.write( "16/3. Find the numbers. \n" );
document.write( "
Algebra.Com's Answer #779226 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "If the two numbers are in the ratio 3:1, then their reciprocals are in the ratio 1:3. \n" ); document.write( "So divide the given sum of the reciprocals, 16/3, into two parts in the ratio 1:3. Those two parts are 4/3 and 12/3=4. \n" ); document.write( "Since the reciprocals are 4/3 and 4, the two numbers are 3/4 and 1/4. \n" ); document.write( " \n" ); document.write( " |