document.write( "Question 1156499: Train A has a speed 25 miles per hour greater than that of train B. If train A travels 240 miles in the same times train B travels 165 miles, what are the speeds of the two trains?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #779212 by ikleyn(52795)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "Let the train A speed be x mph;  then the train B speed is (x-25) mph.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The time equation is\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    \"240%2Fx\" = \"165%2F%28x-25%29\",   or\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    \"48%2Fx\" = \"33%2F%28x-25%29\".\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Cross multiply and continue step by step\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    48*(x-25) = 33x\r\n" );
document.write( "\r\n" );
document.write( "    48x - 48*25 = 33x\r\n" );
document.write( "\r\n" );
document.write( "    48x - 33x = 48*25\r\n" );
document.write( "\r\n" );
document.write( "    15x = 48*25\r\n" );
document.write( "\r\n" );
document.write( "      x = 16*5 = 80.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER.   Train A speed is 80 mph.  Train B speed is 80-25 = 55 mph.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );