document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1156472>Question 1156472</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that ​$2500 is invested in an account that pays interest compounded continuously. Find the amount of time that it would take for the account to grow to ​$3400 at a 4.75​% interest rate.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #779184 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=779184\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P=Poe^rt with continuous compounding<BR>\n" );
document.write( "3400=2500*e^(0.0475t)<BR>\n" );
document.write( "3400/2500=1.36=e^.0475t<BR>\n" );
document.write( "ln of both sides<BR>\n" );
document.write( "0.3075=0.0475 t, the e goes away.<BR>\n" );
document.write( "divide by 0.0475 both sides\r<BR>\n" );
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document.write( "t=6.47 years, rounding at the end.<BR>\n" );
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