document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107078>Question 107078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How  would I write the equation of a line that has slope -3 and contain the point(4,2).express final equation in standard form. Showing me how to solve this would be of great assistance.\r<BR>\n" );
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document.write( "Thank you,<BR>\n" );
document.write( "Brina </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77918 by </B><A HREF=/tutors/aboutme.mpl?userid=Annabelle1><B>Annabelle1(69)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Annabelle1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you use your point-gradient formula again<BR>\n" );
document.write( "y-y1=m(x-x1)\r<BR>\n" );
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document.write( "where m=-3 and x1,y1 is your point (4,2)<BR>\n" );
document.write( "(x1=4,y1=2)\r<BR>\n" );
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document.write( "subbing into the equation<BR>\n" );
document.write( "y-2=-3(x-4)\r<BR>\n" );
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document.write( "expand<BR>\n" );
document.write( "y-2=-3x+12<BR>\n" );
document.write( "y+3x-2-12=0<BR>\n" );
document.write( "y+3x-14=0 </SPAN>\n" );
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