document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1156482>Question 1156482</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A cylinder with a height of 4yds and a base diameter of 6yds is shown. find the surface area in terms of pi </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #779175 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=779175\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This unrolls into a rectangle with length2 pi*rand height 4.  There are two end circles with area pi*r^2\r<BR>\n" );
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document.write( "A=2pi*r*h+2pi*r^2<BR>\n" );
document.write( "=2*pi*3*4+2 pi*9<BR>\n" );
document.write( "=42 pi yds ^2<BR>\n" );
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