document.write( "Question 1156482: A cylinder with a height of 4yds and a base diameter of 6yds is shown. find the surface area in terms of pi \n" ); document.write( "
Algebra.Com's Answer #779174 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "To find the surface area of a cylinder add the surface area of each end plus the surface area of the side. \r
\n" ); document.write( "\n" ); document.write( "Each end is a circle so the surface area of each end is \"pi%2Ar%5E2\", where \"r\" is the radius of the end. There are two ends so their combined surface area is \"2pi%2Ar%5E2\".\r
\n" ); document.write( "\n" ); document.write( "the surface area of the side is \"pi%2Ad%2Ah\"=>\"2pi%2Ar%2Ah\"\r
\n" ); document.write( "\n" ); document.write( "The entire formula for the surface area of a cylinder is \r
\n" ); document.write( "\n" ); document.write( "\"SA=2pi%2Ar%5E2+%2B+2pi%2Ar%2Ah\"\r
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\n" ); document.write( "\n" ); document.write( "given: \r
\n" ); document.write( "\n" ); document.write( "a height of \"h=4yd\" \r
\n" ); document.write( "\n" ); document.write( "and a base diameter of \"d=6yd\"=>\"r=3yd\"\r
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\n" ); document.write( "\n" ); document.write( "\"SA=2pi%2A%283yd%29%5E2+%2B+2pi%2A%283yd%29%2A%284yd%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"SA=2pi%2A9yd%5E2+%2B+2pi%2A12yd%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"SA=18pi%2Ayd%5E2+%2B+24pi%2Ayd%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"SA=42pi%2Ayd%5E2+\"\r
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