document.write( "Question 1156480: Please help me answer this question:\r
\n" ); document.write( "\n" ); document.write( "If log3 (5)= a and log3 (6)=b, express log3 (20) in terms of a and b
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Algebra.Com's Answer #779172 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If \"log%283%2C5%29=+a+\"\r
\n" ); document.write( "\n" ); document.write( "\"+log%283+%2C6%29=b+\"=> \"log%283+%2C2%2A3%29=b\" => \"log%283+%2C2%29%2Blog%283+%2C3%29=b\"=> \"log%283+%2C2%29%2B1=b\"=> \"+log%283+%2C2%29=b-1\"\r
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\n" ); document.write( "\n" ); document.write( "express \"log%283+%2C20%29\" in terms of \"a\" and \"b\"\r
\n" ); document.write( "\n" ); document.write( "\"log%283+%2C20%29+=log%283+%2C2%5E2%2A5%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"log%283+%2C20%29+=log%283+%2C2%5E2%29%2Blog%283+%2C5%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"log%283+%2C20%29+=2log%283+%2C2%29%2Blog%283+%2C5%29\" .......substitute \"log%283+%2C2%29\" and \"log%283+%2C5%29\" from equations above\r
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\n" ); document.write( "\n" ); document.write( "\"log%283+%2C20%29+=2%28b-1%29%2Ba\"\r
\n" ); document.write( "\n" ); document.write( "\"log%283+%2C20%29+=a%2B2b-1\"\r
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