document.write( "Question 1156463: The length of a rectangular box is 4 times its height, and its width is 2 ft more than its height.
\n" ); document.write( "Use the graphing calculator to find the height of the box. Round the answer to two decimal places. \n" ); document.write( "
Algebra.Com's Answer #779160 by ankor@dixie-net.com(22740)\"\" \"About 
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The length of a rectangular box is 4 times its height, and its width is 2 ft more than its height.
\n" ); document.write( "Use the graphing calculator to find the height of the box.
\n" ); document.write( " Round the answer to two decimal places.
\n" ); document.write( ":
\n" ); document.write( "let x = the height
\n" ); document.write( "then
\n" ); document.write( "4x = the length
\n" ); document.write( "and
\n" ); document.write( "(x+2) = then width
\n" ); document.write( "therefore
\n" ); document.write( "vol = 4x * (x+2) * x
\n" ); document.write( "v = 4x^3 + 8x^2
\n" ); document.write( "At this point it seems we should be given the volume of this box, like v = 64
\n" ); document.write( "4x^3 + 8x^2 = 64
\n" ); document.write( "4x^3 + 8x^2 - 64 = 0
\n" ); document.write( "simplify, divide to 4
\n" ); document.write( "x^3 + 2x^2 - 16 = 0
\n" ); document.write( "on a graphing calc
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-4%2C+5%2C+-10%2C+10%2C+x%5E3%2B2x%5E2-16%29+\"
\n" ); document.write( "x = 2 is the height \n" ); document.write( "
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