document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107079>Question 107079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I would really appreciate it if someone could help me solve this problem, write the equation of the line perpendicular to y=1/3x+5 and contains the point(1,4). The final equation has to be expressed in standard form.\r<BR>\n" );
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document.write( "Thank you,<BR>\n" );
document.write( "Brina </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77914 by </B><A HREF=/tutors/aboutme.mpl?userid=Annabelle1><B>Annabelle1(69)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Annabelle1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77914\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the line y=1/3x+5 has a gradient of 1/3 (the coefficient of the x value when y is the subject of the formula)<BR>\n" );
document.write( "the line perpendicular is going to have -3/1 as the gradient (if two line are perpendicular the gradients are the negative recipricol of each other so I flipped 1/3 up-side-down and stuck a negative infront. \r<BR>\n" );
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document.write( "Now you have the gradient of the new line and a point, you use the point-gradient formula\r<BR>\n" );
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document.write( "y-y1=m(x-x1)\r<BR>\n" );
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document.write( "where x1 and y1 are the coordinates you are given (x1=1, y1=4) and m=-3/1=-3\r<BR>\n" );
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document.write( "subbing in:<BR>\n" );
document.write( "y-4=-3(x-1)<BR>\n" );
document.write( "y-4=3x+3<BR>\n" );
document.write( "y-3x-7=0 </SPAN>\n" );
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