document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107088>Question 107088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can't remember how to do this type of problem, someone please help me I will be so thankful. Find three consecutive intergers whose sum is 93.\r<BR>\n" );
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document.write( "Brina </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77912 by </B><A HREF=/tutors/aboutme.mpl?userid=Annabelle1><B>Annabelle1(69)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Annabelle1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77912\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let your three consecutive numbers be x , x+1 and x+2\r<BR>\n" );
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document.write( "the sum of these are x+(x+1)+(x+2) which simplifies to 3x+3<BR>\n" );
document.write( "This is equal to 93 so 3x+3=93<BR>\n" );
document.write( "minus 3 from both sides<BR>\n" );
document.write( "3x+3-3=93-3<BR>\n" );
document.write( "3x=90\r<BR>\n" );
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document.write( "divivde both sides by 3<BR>\n" );
document.write( "x=30\r<BR>\n" );
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document.write( "The first integer is 30 so the following two are 31 and 32 </SPAN>\n" );
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