document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107080>Question 107080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with the steps in solving this problem. It says solve by substitution 3x-5y=41, x-y=11\r<BR>\n" );
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document.write( "Thank you,<BR>\n" );
document.write( "Brina </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77903 by </B><A HREF=/tutors/aboutme.mpl?userid=Annabelle1><B>Annabelle1(69)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Annabelle1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> make x the subject of the formula for the second equation so it becomes<BR>\n" );
document.write( "x=11+y. Substitute this into the first equation.\r<BR>\n" );
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document.write( "it then becomes<BR>\n" );
document.write( "3(11+y)-5y=41<BR>\n" );
document.write( "33+3y-5y=41<BR>\n" );
document.write( "33-2y=41<BR>\n" );
document.write( "-2y=41-33<BR>\n" );
document.write( "-2y=8<BR>\n" );
document.write( "y=8/(-2)<BR>\n" );
document.write( "y=-4\r<BR>\n" );
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document.write( "sub this value into x=11+y to get you x value<BR>\n" );
document.write( "x=11+-4<BR>\n" );
document.write( "x=7 </SPAN>\n" );
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