document.write( "Question 1156281: Bruce wants to make 50 ml of an alcohol solution with a 12% concentration. He has a 10% alcohol solution and a 15% alcohol solution. The equation 0.10x + 0.15(50 - x) = 0.12(50) can be used to find the amount of 10% alcohol solution Bruce should use.\r
\n" ); document.write( "\n" ); document.write( "How much of the 10% alcohol solution should Bruce use?\r
\n" ); document.write( "\n" ); document.write( " mL\r
\n" ); document.write( "\n" ); document.write( "How much of the 15% alcohol solution should Bruce use?\r
\n" ); document.write( "\n" ); document.write( " mL
\n" ); document.write( "

Algebra.Com's Answer #778972 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
---------------------------------
\n" ); document.write( "..., make 50 ml of an alcohol solution with a 12% concentration. He has a 10% alcohol solution and a 15% alcohol solution.
\n" ); document.write( "---------------------------------\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If want x of the 10% alcohol, then use 50-x of the 15% alcohol.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Accounting for quantities of alcohol to give the expected amount of pure alcohol: \"0.10x%2B0.15%2850-x%29=0.12%2A50\";\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"0.1x%2B0.15%2A50-0.15x=0.12%2A50\"\r
\n" ); document.write( "\n" ); document.write( "\"%280.1-0.15%29x=0.12%2A50-0.15%2A50\"\r
\n" ); document.write( "\n" ); document.write( "\"%280.15-0.1%29x=0.15%2A50-0.12%2A50\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=50%28%280.15-0.12%29%2F%280.15-0.1%29%29%29\", and you can finish this.
\n" ); document.write( "
\n" );