document.write( "Question 1156273: I am 4 times as old as my son and the difference is 33 years. How old am I?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #778961 by ikleyn(52873) You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Let x be the son's age; then your age is 3x, according to the condition.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Also, the problem says that\r\n" ); document.write( "\r\n" ); document.write( " 4x - x = 33.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Hence,\r\n" ); document.write( "\r\n" ); document.write( " 3x = 33 and x = 33/3 = 11.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Your son's age is 11; your age is 4*11 = 44.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. You are 44 years old.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |