document.write( "Question 1156261: I REALLY need help with this equation it goes like this : -3/4=k-1/3 and then it says solve for K, would u mind and help me on this please? thank you!
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Algebra.Com's Answer #778954 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Put a 1 under the k so that everything will be a fraction\r\n" );
document.write( "with a numerator and a denominator:\r\n" );
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document.write( "The denominators are 4,1,3.  They can all be divided into 12,\r\n" );
document.write( "which is their LCM or LCD.  So we will multiply all the terms by \r\n" );
document.write( "12. But first let's put parentheses around all the terms:\r\n" );
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document.write( "Now we multiply every term by \r\n" );
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document.write( "           \"%2812%5E%22%22%2F1%5E%22%22%29\"\r\n" );
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document.write( "and get:\r\n" );
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document.write( "Then we cancel \r\n" );
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document.write( "All that is left, when we ignore the denominators of 1, is this\r\n" );
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document.write( "Then we add +4 to both sides:\r\n" );
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document.write( "\"matrix%281%2C5%2C%0D%0A%0D%0A-5%2C%22%22%2C%22%22=%22%22%2C%22%22%2C12k%29\"\r\n" );
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document.write( "Then we divide both sides by 12\r\n" );
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document.write( "\"matrix%281%2C5%2C%0D%0A%0D%0A-5%2F12%2C%22%22%2C%22%22=%22%22%2C%22%22%2C12k%2F12%29\"\r\n" );
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document.write( "Then we cancel the 12's\r\n" );
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document.write( "And finally we have:\r\n" );
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document.write( "\"matrix%281%2C5%2C%0D%0A%0D%0A-5%2F12%2C%22%22%2C%22%22=%22%22%2C%22%22%2Ck%29\"\r\n" );
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document.write( "Edwin
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