document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107074>Question 107074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In triangle ABC, AB is 9 cm. shorter that AC, while BC is 3 cm. longer than AC.  If the perimeter of the triangle is 48 cm. find the lengths of the three sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77894 by </B><A HREF=/tutors/aboutme.mpl?userid=Annabelle1><B>Annabelle1(69)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Annabelle1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77894\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the length of AC be X<BR>\n" );
document.write( "so.....<BR>\n" );
document.write( "AC=x<BR>\n" );
document.write( "BC=x+3<BR>\n" );
document.write( "AB=x-9\r<BR>\n" );
document.write( "\n" );
document.write( "adding the sides together to find the perimeter\r<BR>\n" );
document.write( "\n" );
document.write( "x+ (x+3) + (x-9) = 48<BR>\n" );
document.write( "3x-6=48<BR>\n" );
document.write( "3x=54<BR>\n" );
document.write( "x=18<BR>\n" );
document.write( "so AC=18<BR>\n" );
document.write( "BC= 18+3=21<BR>\n" );
document.write( "AB=18-9=9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );