document.write( "Question 1156243: A batting order must be created from the 9 starters on a baseball team. How many batting orders are possible if Jack has to go up to 4th? \n" ); document.write( "
Algebra.Com's Answer #778939 by Edwin McCravy(20065)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "Choose the most restrictive things first, which is the 4th batter.\r\n" );
document.write( " There is only 1 player to choose for the 4th batter (as Jack).\r\n" );
document.write( "Then there are 8 remaining players to choose for the 1st batter.\r\n" );
document.write( "Then there are 7 remaining players to choose for the 2nd batter. \r\n" );
document.write( "Then there are 6 remaining players to choose for the 3rd batter.\r\n" );
document.write( "Then there are 5 remaining players to choose for the 5th batter.\r\n" );
document.write( "Then there are 4 remaining players to choose for the 6th batter.\r\n" );
document.write( "Then there are 3 remaining players to choose for the 7th batter.\r\n" );
document.write( "Then there are 2 remaining players to choose for the 8th batter.\r\n" );
document.write( "Then there are 1 remaining players to choose for the 9th batter\r\n" );
document.write( "\r\n" );
document.write( "Answer 1∙8∙7∙6∙5∙4∙3∙2∙1 = 1∙8! = 8! = 40320\r\n" );
document.write( "\r\n" );
document.write( "Edwin

\n" ); document.write( " \n" ); document.write( "
\n" );