document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=107013>Question 107013</A>: <I><SPAN STYLE=\"word-break: break-all;\"> luoise walked for 2 hours then ran for 1.5 hours if she ran twice as long as she walks and the total trip was 20 miles the how fast did she run?\r<BR>\n" );
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document.write( "I am working on trying to set this up i have x to equal walking spd and 2x for running speed  I know the rate is 3.5 hours together woulit be 3.5 = (x + 2x) / 20 ???  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77890 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77890\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am working on trying to set this up i have x to equal walking spd and 2x for running speed I know the rate is 3.5 hours together woulit be 3.5 = (x + 2x) / 20 ??? \r<BR>\n" );
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document.write( "AT LEAST YOU ARE GIVING IT A SHOT BUT I THINK YOU ARE TRYING TO MAKE IT HARDER THAN IT REALLY IS.  TRY TO FOLLOW MY APPROACH. \r<BR>\n" );
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document.write( "distance(d) equals rate(r) times time(t) or d=rt; r=d/t and t=d/r\r<BR>\n" );
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document.write( "I'm assuming you mean \"-----twice as fast---not twice as long--\"\r<BR>\n" );
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document.write( "AS YOU HAVE DONE, WE'LL LET:<BR>\n" );
document.write( "Let x=walking speed<BR>\n" );
document.write( "Then 2x=running speed\r<BR>\n" );
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document.write( "Distance she walks=x*2 or 2x (rate she walks times time)\r<BR>\n" );
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document.write( "Distance she runs=2x*1.5 or 3x (rate she runs times time)<BR>\n" );
document.write( "Now we know (actually we are told) that the distance she walks plus the distance she runs equals 20 mi, so:\r<BR>\n" );
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document.write( "2x+3x=20 collect like terms<BR>\n" );
document.write( "5x=20  divide both sides by 5<BR>\n" );
document.write( "x=4 mi/hr-----------------------------walking speed<BR>\n" );
document.write( "2x=2*4=8 mi/hr-----------------------------running speed\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "2*4+1.5*8=20<BR>\n" );
document.write( "8+12=20<BR>\n" );
document.write( "20=20\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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