document.write( "Question 1156186: what is the amplitude, period, and phase shift of f(x)= -3sin(4x-pi)-5? \n" ); document.write( "

Algebra.Com's Answer #778878 by ikleyn(52858) $\"\"$ $\"About$

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document.write( "1)  Amplitude is ALWAYS positive value and NEVER is negative value, by the definition.\r\n" );
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document.write( "    So, in this problem the amplitude is |-3| = 3.\r\n" );
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document.write( "        NOT  -3  (!) (!) (!)\r\n" );
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document.write( "2)  The parent function to measure the shift in this problem  IS NOT -3sin(4x) - 5, as @Mathlover MISTAKENLY thinks \r\n" );
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document.write( "     and determines the phase shift incorrectly.\r\n" );
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document.write( "    To determine the shift, the given function should be presented wit POSITIVE amplitude\r\n" );
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document.write( "        -3sn(4x-pi) - 5 = 3sin(4x) - 5\r\n" );
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document.write( "    which shows that the phase shift is 0 (zero, ZERO) in this case.\r\n" );
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document.write( "See the plot below.\r\n" );
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document.write( "    \r\n" );
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document.write( "    Plot y = -3*sin(4x-3.14) - 5\r\n" );
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document.write( "Thus regarding the amplitude and the phase shift, the answers by @MathLower1 are incorrect.\r\n" );
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document.write( "Edwin correctly found the amplitude as positive 3, but regarding the phase shift, he dodged a direct answer.\r\n" );
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