document.write( "Question 1156187: Please help me with this related rates question
\n" ); document.write( "if two resistors with resistances R1 and R2 are connected in parallel, as in the figure below, then the total resistance R, measured in ohms (Ω), is given by
\n" ); document.write( "1/R = 1/R1+1/R2\r
\n" ); document.write( "\n" ); document.write( "If R1 and R2 are increasing at rates of 0.3 Ω/s and 0.2 Ω/s, respectively, how fast is R changing when R1 = 80 Ω and R2 = 100 Ω? (Round your answer to three decimal places.)
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Algebra.Com's Answer #778866 by Boreal(15235)\"\" \"About 
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1/R=1/80+1/100; multiply by LCD of 400R and 400=5R+4R=9R, so R=400/9=44.44 ohms\r
\n" ); document.write( "\n" ); document.write( "R^(-1)=(R1)^(-1)+R2^(-1)
\n" ); document.write( "-1/R^2 dR/ds=-1/R1^2 dR1/ds-1/R2^2 dR2/ds
\n" ); document.write( "-1/1975.31 dR/ds=-1/6400*0.3-1/10000*0.2
\n" ); document.write( "so
\n" ); document.write( "-0.000506 dR/ds=-0.0000469-0.00002=-0.0000669. Change all signs and divide by 0.000506
\n" ); document.write( "dR/ds=0.132 ohms/sec.
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