document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1156150>Question 1156150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find measure of angle q to the nearest degree\r<BR>\n" );
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document.write( "http://prntscr.com/rzxssa </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #778827 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=778827\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "Problem:<BR>\n" );
document.write( "Given triangle PQR is acute with <BR>\n" );
document.write( "<ul><li>QR = 9.7</li><li>PR = 12.2</li><li>angle P = 43 degrees</li></ul>find the measure of angle Q\r<BR>\n" );
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document.write( "The diagram would look something like this<BR>\n" );
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document.write( "Use the law of sines to solve for angle Q<BR>\n" );
document.write( "sin(A)/a = sin(B)/b<BR>\n" );
document.write( "sin(P)/p = sin(Q)/q<BR>\n" );
document.write( "sin(P)/QR = sin(Q)/PR<BR>\n" );
document.write( "sin(43)/9.7 = sin(Q)/12.2<BR>\n" );
document.write( "sin(Q)/12.2 = sin(43)/9.7<BR>\n" );
document.write( "sin(Q) = 12.2*(sin(43)/9.7)<BR>\n" );
document.write( "sin(Q) = 0.85777113327449<BR>\n" );
document.write( "Q = arcsin(0.85777113327449)<BR>\n" );
document.write( "Q = 59.067239465619<BR>\n" );
document.write( "Q = 59<BR>\n" );
document.write( "Make sure your calculator is in degree mode. Arcsine is the same as inverse sine. Remember to round to the nearest degree. \r<BR>\n" );
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document.write( "Note: There is another triangle possible, but that would mean angle Q is over 90 degrees. This is because Q = 180-arcsin(0.85777113327449) = 180-59.067239465619 = 120.932760534381. So we ignore this possible Q value. Recall that triangle PQR is acute meaning that all 3 angles must be less than 90. \r<BR>\n" );
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document.write( "Answer: <font color=red>approximately 59 degrees</font><BR>\n" );
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