document.write( "Question 1156080: Solve the formula for the indicated variable. (Simplify your answer completely.) See Example 4. (Objective 2)
\n" ); document.write( "A = 2πr2 + 2πhr, for r\r
\n" ); document.write( "\n" ); document.write( "(The formula for the surface area of a right circular cylinder)
\n" ); document.write( "r =
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Algebra.Com's Answer #778776 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "\n" ); document.write( "\"A+=+2pi%2Ar%5E2+%2B+2pi%2Ahr\"\r
\n" ); document.write( "\n" ); document.write( "solve for \"r\"\r
\n" ); document.write( "\n" ); document.write( "\"A+=+2pi%28r%5E2+%2B+hr%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A%2F2pi=r%5E2+%2B+hr\".......complete square\r
\n" ); document.write( "\n" ); document.write( "\"A%2F2pi=%28r%5E2+%2B+hr%2Bb%5E2%29-b%5E2\".....\"b=h%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"A%2F2pi=%28r%5E2+%2B+hr%2B%28h%2F2%29%5E2%29-%28h%2F2%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"A%2F2pi=%28r%2Bh%2F2%29%5E2-h%5E2%2F4\"\r
\n" ); document.write( "\n" ); document.write( "\"A%2F2pi%2Bh%5E2%2F4=%28r%2Bh%2F2%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28A%2F2pi%2Bh%5E2%2F4%29=r%2Bh%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"r=sqrt%28A%2F2pi%2Bh%5E2%2F4%29-h%2F2\"\r
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