document.write( "Question 1156080: Solve the formula for the indicated variable. (Simplify your answer completely.) See Example 4. (Objective 2)
\n" ); document.write( "A = 2πr2 + 2πhr, for r\r
\n" ); document.write( "\n" ); document.write( "(The formula for the surface area of a right circular cylinder)
\n" ); document.write( "r =
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Algebra.Com's Answer #778775 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "A = 2πr2 + 2πhr, solve for r.
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\n" ); document.write( "\n" ); document.write( "\"A=2pi%2Ar%5E2%2B2pi%2Ahr\"\r
\n" ); document.write( "\n" ); document.write( "\"2pi%2Ar%5E2%2B2pi%2Ahr-A=0\"\r
\n" ); document.write( "\n" ); document.write( "\"r=%28-2pi%2Ah%2B-+sqrt%284h%5E2%2Api%5E2%2B8pi%2AA%29%29%2F%284pi%29\"\r
\n" ); document.write( "\n" ); document.write( "\"r=%28-2h%2Api%2B-+2%2Asqrt%28pi%2Ah%5E2%2B2A%2Api%29%29%2F%284pi%29\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28r=%28-h%2Api%2B-+sqrt%28pi%2Ah%5E2%2B2A%2Api%29%29%2F%282pi%29%29\"
\n" ); document.write( "(Look for any mistakes.)
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