document.write( "Question 1155974: Perform a first derivative test on the function f(x)= 2x^3+3x^2-120x+2; [-5,7].
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Algebra.Com's Answer #778762 by MathLover1(20850)\"\" \"About 
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\"f%28x%29=+2x%5E3%2B3x%5E2-120x%2B2\"\r
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\n" ); document.write( "\n" ); document.write( "a. Locate the critical points of the given function.\r
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\n" ); document.write( "\n" ); document.write( "find first derivative\r
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\n" ); document.write( "\n" ); document.write( "\"f\"'\"+%28x%29+=6x%5E2%2B6x-120\"\r
\n" ); document.write( "\n" ); document.write( "set \"f\"'\"+%28x%29+=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"6x%5E2%2B6x-120=0\"\r
\n" ); document.write( "\n" ); document.write( "\"6%28x%5E2%2Bx-20%29=0\"\r
\n" ); document.write( "\n" ); document.write( "will be zero if\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2Bx-20=0\".....factor\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-4x%2B5x-20=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2-4x%29%2B%285x-20%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%28x-4%29%2B5%28x-4%29=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x+-+4%29+%28x+%2B+5%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "=> extreme points are at\r
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\n" ); document.write( "\n" ); document.write( "\"x=4\" and \"x=-5\"\r
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\n" ); document.write( "\n" ); document.write( "use second derivative test to determine where is max and where is min\r
\n" ); document.write( "\n" ); document.write( "\"f\"''\"%28x%29+=12x%2B6\"\r
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\n" ); document.write( "\n" ); document.write( "\"f\"''\"%28-5%29+=12%28-5%29%2B6=-54\" => negative, the absolute maximum is at\"+-5\"\r
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\n" ); document.write( "\n" ); document.write( "\"f\"''\"%284%29+=12%284%29%2B6=54\" => positive, the absolute minimum is at \"4\"\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-15%2C+15%2C+-500%2C+500%2C+2x%5E3%2B3x%5E2-120x%2B2%29+\" \r
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