document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1156060>Question 1156060</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An Object is thrown upward from the top of a 48-foot building with an initial velocity of 8 feet per second. The height \"h\" of the object after \"t\" seconds is given by the quadratic equation \"h=-16t^2+8t+48\" When will the object hit the ground? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #778754 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=778754\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> h=-16t^2+8t+48=16t^2-8t-48, changing all signs<BR>\n" );
document.write( "hits the ground when h=0<BR>\n" );
document.write( "factor out an 8<BR>\n" );
document.write( "2t^2-t-6=0<BR>\n" );
document.write( "t^2-t-12<BR>\n" );
document.write( "(t-2)(2t+3)=0<BR>\n" );
document.write( "t=2, -3/2, use positiver root of 2 seconds, answer.<BR>\n" );
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