document.write( "Question 1156061: A store sells about 80 sweaters per month at a price of $ 30. For each $ 1 decrease in price, the store sells 5 more sweaters per month. Write a function that models this situation. Tell how the store can maximize monthly revenue. \n" ); document.write( "
Algebra.Com's Answer #778753 by josmiceli(19441)\"\" \"About 
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Let \"+R+\" = monthly revenue
\n" ); document.write( "Let \"+n+\" = number of $1 decreases in price
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\n" ); document.write( "\"+R+=+%28+30+-+1%2An+%29%2A%28+80+%2B+5n+%29+\"
\n" ); document.write( "\"+R+=+2400+-+80n+%2B+150n+-+5n%5E2+\"
\n" ); document.write( "\"+R+=+-5n%5E2+%2B+70n+%2B+2400+\"
\n" ); document.write( "The n-value of the peak is at:
\n" ); document.write( "\"+n%5Bmax%5D+=+-b%2F%282a%29+\"
\n" ); document.write( "\"+n%5Bmax%5D+=+-70%2F%28+2%2A%28-5%29%29+\"
\n" ); document.write( "\"+n%5Bmax%5D+=+7+\"
\n" ); document.write( "-----------------------
\n" ); document.write( "If the store lowers the price by $7, the
\n" ); document.write( "monthly revenue will be maximum
\n" ); document.write( "---------------------------------------
\n" ); document.write( "Here's the plot of \"+R+\" and \"+n+\":
\n" ); document.write( "\"+graph%28+500%2C+500%2C+-2%2C+20%2C+-300%2C+3000%2C+-5x%5E2+%2B+70x+%2B+2400+%29+\"
\n" ); document.write( "The maximum revenue is:
\n" ); document.write( "\"+R%5Bmax%5D+=+%28+30+-+1%2A7+%29%2A%28+80+%2B+5%2A7+%29+\"
\n" ); document.write( "\"+R%5Bmax%5D+=+23%2A115+\"
\n" ); document.write( "\"+R%5Bmax%5D+=+2645+\"
\n" ); document.write( "$2,645 \r
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