document.write( "Question 1156002: Please help me with this related rates question
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Algebra.Com's Answer #778692 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "We let the ladder slip down the wall, then we \r\n" );
document.write( "\"freeze\" it at an instant.\r\n" );
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document.write( "z is the length of the ladder, so it is constant.\r\n" );
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document.write( "y is a variable speed, getting shorter and shorter with \r\n" );
document.write( "respect to time.\r\n" );
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document.write( "dy/dt is a variable speed, getting faster and faster due \r\n" );
document.write( "to gravity, with respect to time. \r\n" );
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document.write( "x is a variable getting longer with respect to time.\r\n" );
document.write( "dx/dt is a variable, getting slower and slower. \r\n" );
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document.write( "[Important: do not make the mistake of substituting the \r\n" );
document.write( "\"freezing' value of the variables x, until we \r\n" );
document.write( "have done the calculus letting them vary. Leave the variables\r\n" );
document.write( "as they are until we have taken derivatives.]\r\n" );
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document.write( "We use the Pythagorean theorem:\r\n" );
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document.write( "\"x%5E2%2By%5E2=z%5E2\"\r\n" );
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document.write( "We take derivatives with respect to t (time), remembering\r\n" );
document.write( "that since the length of the ladder z is the ONLY constant, \r\n" );
document.write( "the derivative of z² is 0.\r\n" );
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document.write( "\"2x%2Aexpr%28dx%2Fdt%29%2B2y%2Aexpr%28dy%2Fdt%29=0\"\r\n" );
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document.write( "Divide through by 2\r\n" );
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document.write( "\"x%2Aexpr%28dx%2Fdt%29%2By%2Aexpr%28dy%2Fdt%29=0\"\r\n" );
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document.write( "Now that we have taken the derivative we can substitute the \r\n" );
document.write( "\"freezing\" values:\r\n" );
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document.write( "We are given that the top of a ladder slides down the\r\n" );
document.write( "wall at a rate of 0.125 m/s, since y is getting shorter,\r\n" );
document.write( "the rate y is changing is negative or -0.125 m/s.\r\n" );
document.write( "We \"freeze\" the variable x at 5 m. We \"freeze\" dx/dt at\r\n" );
document.write( "0.3 m/s.\r\n" );
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document.write( "\"x%2Aexpr%28dx%2Fdt%29%2By%2A%28-0.125%29=0\"\r\n" );
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document.write( "\"5%280.3%29-0.125y=0\"\r\n" );
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document.write( "\"1.5-0.125y=0\"\r\n" );
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document.write( "\"-0.125y=-1.5\"\r\n" );
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document.write( "\"y=%28-1.5%29%2F%28-0.125%29\"\r\n" );
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document.write( "\"y=12\"\r\n" );
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document.write( "So the \"freezing\" value of y is 12 m.\r\n" );
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document.write( "Now we can calculate the length of the ladder z\r\n" );
document.write( "from the Pythagorean theorem:\r\n" );
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document.write( "\"x%5E2%2By%5E2=z%5E2\"\r\n" );
document.write( "\"5%5E2%2B12%5E2=z%5E2\"\r\n" );
document.write( "\"25%2B144=z%5E2\"\r\n" );
document.write( "\"169=z%5E2\"\r\n" );
document.write( "\"sqrt%28169%29=z\"\r\n" );
document.write( "\"13=z\"\r\n" );
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document.write( "So the ladder is 13 m long.\r\n" );
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document.write( "Edwin

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