document.write( "Question 107040: i need help solving these quadratic equations using the quadratic formula.
\n" ); document.write( "2x^2 - 5x = 3\r
\n" ); document.write( "\n" ); document.write( "3x^2 - 2x + 1 = 0
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Algebra.Com's Answer #77869 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
The quadratic formula starts with the equation:
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\n" ); document.write( "\"ax%5E2+%2B+bx+%2B+c+=+0\"
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\n" ); document.write( "in which:
\n" ); document.write( "\"a\" is the multiplier of the term containing \"x%5E2\"
\n" ); document.write( "\"b\" is the multiplier of the term containing \"x\"
\n" ); document.write( "and \"c\" is the constant.
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\n" ); document.write( "Notice also that the right side of this equation is zero.
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\n" ); document.write( "For an equation of this form, the answer is given by the equation:
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\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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\n" ); document.write( "Your first equation is \"2x%5E2+-+5x+=+3\". Notice that this equation is not in the form
\n" ); document.write( "required by the quadratic formula because the right side is not zero. Therefore, you need
\n" ); document.write( "to make the right side equal to zero, and you can do that by subtracting 3 from both sides
\n" ); document.write( "to make the equation become:
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\n" ); document.write( "\"2x%5E2+-+5x+-3+=+0\"
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\n" ); document.write( "Now you can compare each term of this equation to the standard quadratic equation.
\n" ); document.write( "If you do, you can see that:
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\n" ); document.write( "\"a\" is +2 because it is the multiplier of the \"x%5E2\" term
\n" ); document.write( "\"b\" is -5 because it is the multiplier of the \"x\" term
\n" ); document.write( "and \"c\" is -3 because it is the constant term
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\n" ); document.write( "Now all you need to do is to substitute these values into the equation for x:
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\n" ); document.write( "Then all you need to do is simplify the right side of this equation:
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\n" ); document.write( "\"x+=+%285+%2B-+sqrt%2825+%2B+24%29%29%2F4+=+%285+%2B-+sqrt%2849%29%29%2F4\"
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\n" ); document.write( "Note that the square root of 49 is +7. Substituting that value into this equation
\n" ); document.write( "indicates that you have two answers. The first answer is found by using the + sign in
\n" ); document.write( "the numerator to get:
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\n" ); document.write( "\"x+=+%285%2B7%29%2F4+=+12%2F4+=+3\"
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\n" ); document.write( "and the second answer is found by using the - sign in the numerator to get:
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\n" ); document.write( "\"x+=+%285-7%29%2F4+=+-2%2F4+=+-1%2F2\"
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\n" ); document.write( "So the two answers to this problem are \"x+=+%2B3\" and \"x+=+-1%2F2\"
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\n" ); document.write( "This is the same method as you use in the second problem ... you are given the problem:
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\n" ); document.write( "\"3x%5E2+-+2x+%2B+1+=+0\"
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\n" ); document.write( "This is already in the standard quadratic form and you can immediately say that:
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\n" ); document.write( "\"a\" = +3
\n" ); document.write( "\"b\" = -2
\n" ); document.write( "and \"c\" = +1
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\n" ); document.write( "Substitute these values into the equation for the answer x and you get:
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\n" ); document.write( "Simplifying the right side:
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\n" ); document.write( "\"x+=+%282%2B-sqrt%284-12%29%29%2F6=+%282%2B-sqrt%28-8%29%29%2F6\"
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\n" ); document.write( "This is a little trickier problem than the first one because it contains the square root
\n" ); document.write( "of a negative number and therefore you get a complex number as the answer (that is your
\n" ); document.write( "answer has both a real part and an imaginary part). If you are familiar with complex numbers,
\n" ); document.write( "you may recall that \"i\" is defined as \"sqrt%28-1%29\" so that \"i%5E2+=+-1\". Therefore,
\n" ); document.write( "you can substitute \"i%5E2\" for \"+-1\". When you do, the equation for x becomes:
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\n" ); document.write( "Note that \"sqrt%28i%5E2%29+=+i\" and \"sqrt%288%29+=+sqrt%284%2A2%29+=+sqrt%284%29%2Asqrt%282%29+=+2%2Asqrt%282%29\".
\n" ); document.write( "When you substitute these simplifications into the equation for x it becomes:
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\n" ); document.write( "\"x+=+%282%2B-i%2A2%2Asqrt%282%29%29%2F6\"
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\n" ); document.write( "Each of the terms in the numerator contains 2 as a factor. Therefore, you can factor out
\n" ); document.write( "this 2 and then divide it by the denominator 6 as follows:
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\n" ); document.write( "\"x+=+%282%2A%281%2B-i%2Asqrt%282%29%29%29%2F6+=+%281%2B-i%2Asqrt%282%29%29%2F3\"
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\n" ); document.write( "Then using the + and - signs of the terms in the numerator, you get for your answers:
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\n" ); document.write( "\"x+=+%281%2Bi%2Asqrt%282%29%29%2F3\" and \"x+=+%281-i%2Asqrt%282%29%29%2F3\"
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\n" ); document.write( "Hope this clarifies these two problems for you and you can see through all the math manipulations
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