document.write( "Question 1155987: A circle is inscribed into a right triangle. The point of tangency divides the hypotenuse in two segments with lengths 2 and 3. Find the radius of the circle \n" ); document.write( "
Algebra.Com's Answer #778680 by greenestamps(13206)\"\" \"About 
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\n" ); document.write( "Let the triangle be ABC, with right angle at C.

\n" ); document.write( "Let P, Q, and R be the points of tangency of the circle with sides AB, BC, and CA, respectively.

\n" ); document.write( "We are given that AP=2 and PB=3.

\n" ); document.write( "Two tangents from an external point to a circle are congruent, so RC=2 and QB=3.

\n" ); document.write( "If r is the radius of the circle, then AC = 2+r and BC = 3+r.

\n" ); document.write( "Then in triangle ABC,

\n" ); document.write( "\"%282%2Br%29%5E2%2B%283%2Br%29%5E2+=+5%5E2\"

\n" ); document.write( "That equation is easily solved to find the radius.

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